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slave
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15 Nov 2015, 3:18 pm

SippingSpiderVenom wrote:
well im happy:) :) :)
now if it was lv-426 I'd have had it right away.


glad to hear :D



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15 Nov 2015, 6:33 pm

So, (4-4)/(4+4)=0
can you get to twenty?


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15 Nov 2015, 6:44 pm

SippingSpiderVenom wrote:
So, (4-4)/(4+4)=0
can you get to twenty?


What do you mean by "can you get to twenty?"?


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15 Nov 2015, 6:47 pm

9474=9^4+4^4+7^4+4^4


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15 Nov 2015, 6:57 pm

okay using four fours apply operations so that you get twenty equations each equal to the set of numbers 1:20

we could count so that it is a group effort.
44/44=1
or (4+4)/(4+4)=1

now you'd find an equation using four fours equal to two.


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Rudin
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15 Nov 2015, 7:04 pm

SippingSpiderVenom wrote:
okay using four fours apply operations so that you get twenty equations each equal to the set of numbers 1:20

we could count so that it is a group effort.
44/44=1
or (4+4)/(4+4)=1

now you'd find an equation using four fours equal to two.




(4-4)+4!-4=
0+24-4=
20

Where 4!=1x2x3x4=24 (the number of ways to arrange 4 objects).


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-Bruce Schneider


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15 Nov 2015, 9:46 pm

Yes, I was thinking we might go in order. I'll do two and three.
(4*4)/(4+4)=2
(4+4+4)/4=3


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15 Nov 2015, 9:50 pm

Okay, sounds good. My teacher actually posed this problem and I completed it, I forget some of the answers though.


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16 Nov 2015, 8:42 am

(4*4)/(sqrt(4)+sqrt(4))=4
((4*4)+4)/(4)=5

(sorry i tend to over use parentheses, it's an artifact from programming I'd rather not get rid of)


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16 Nov 2015, 12:05 pm

sqrt(4)+(4*4)/4=6

(44/4)-4=7



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16 Nov 2015, 4:20 pm

6=(4!/4)+(4-4), this is an alternate solution.


8= (4*sqrt(4))+(4-4)


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16 Nov 2015, 6:04 pm

Rudin wrote:
6=(4!/4)+(4-4), this is an alternate solution.


I like that one. I might adjust it to:

(4!/4)*(4/4)=6

So many choices for this one!

next:

(4/4)+4+4=9



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16 Nov 2015, 6:16 pm

10=(4!/4)+(sqrt(4*4))


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16 Nov 2015, 10:03 pm

(4!/sqrt(4))-(4/4)=11


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slave
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16 Nov 2015, 10:49 pm

Rudin wrote:
10=(4!/4)+(sqrt(4*4))


Rudin, may i ask if you are enrolled in an advanced Maths program or in a regular public school and just teaching yourself Maths? :D



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17 Nov 2015, 7:49 am

slave wrote:
Rudin wrote:
10=(4!/4)+(sqrt(4*4))


Rudin, may i ask if you are enrolled in an advanced Maths program or in a regular public school and just teaching yourself Maths? :D


I go to university classes in the morning on Mondays, Wednesdays and Fridays. I go to public school for the rest of the day. I do my maths homework for public school, but when the teacher is teaching a lesson I just doodle and come up with interesting mathematical ideas, solve interesting problems I find online, or do my university maths coursework. I also have special permission to stay inside and go on the computer or do maths. I find the school cafeteria extremely loud so I eat in the student resource room.

Bright people find clever ways to keep the selves occupied.

So, I go to a regular public school.


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"God may not play dice with the universe, but something strange is going on with prime numbers."

-Paul Erdos

"There are two types of cryptography in this world: cryptography that will stop your kid sister from looking at your files, and cryptography that will stop major governments from reading your files."

-Bruce Schneider


Last edited by Rudin on 17 Nov 2015, 7:53 am, edited 1 time in total.