DentArthurDent wrote:
Oops I Think I have bee incredibly dense Space time is not Euclidean therefore any point on the hyperbolic curve is the same distance to all observers.

Yes?
Sorry, I was going to reply to you but I've been busy lately. Minkowski space-time conforms to hyperbolic geometry rather than Euclidean geometry, so the "distance" between two space-time points is s^2 = (ct)^2 - x^2 - y^2 - z^2 or s^2 = -(ct)^2 +x^2 + z^2, depending on your sign convention rather than the distance given by the Pythagoras theorem for Euclidean space. You can think of it as a "Pythagoras theorem" for hyperbolic geometry, the only difference is that we actually use S = s^2 to define space-time separation, hence why S = (ct)^2 - x^2 in your example, because there are some squared "distances" that are negative.