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bonez
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10 May 2009, 1:34 am

I have this problem on my math hw... is this how I solve it??

In a triangle where side a is opposite angle A, and side b is opposite angle B and so on....
Given A = 31 degrees, B = 23 degrees and c = 112 feet.

So heres what I think I should do. first i do 180 - (A + B) = 126, so C = 126 degrees. Now 126/112 = 23/x , so side b = 20.44 feet..

Is this how to solve the problem?



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10 May 2009, 2:18 am

One way to check your answer would be to reduce the problem down to a pair of right angled triangles. Then use

sine theta = opposite / hypotenuse
cosine theta = adjacent / hypotenuse

But lets do it with the law of sines

Angle C = 180 - (A+B),

So Angle C = 126 degrees

Now Sine C = 0.80902

Now use the following equation

a / (sine A) = b / (sine B) = c / (sine C)

As c is 112 feet,

c / (sine C) = 138.44 feet

Now rearrange the equation

b / (sine B) = c / (sine C)

To b = c (Sine B) / Sine C

Which gives you something very different to the answer you got. I think that you can do the rest yourself, as it is your homework I will not do it for you. My reason for not helping you further right now is that you need to learn, and by doing it yourself you stand a better chance than if I just give you the final answer.

But if you get stuck I think you should consult a maths textbook or one of the maths wizards. You can try PMing me but I can not stay online all day so I might not see your PM until it is too late.

I have just checked the wikipedia article http://en.wikipedia.org/wiki/Right_angl ... and_angles

And it does appear to be correct, I normally do not recomend wikipedia as it is not always correct or well written but the version I just read looks OK and it is correct.

Have fun with your maths.


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bonez
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10 May 2009, 10:21 am

i didnt get what u were doing with the c's, so used a and b. does this look right?

112/sin(126) = x/sin(23) so b=112*sin(23)/sin(126) = 54.09 ft

Thanks



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10 May 2009, 1:50 pm

You got the same answer as me, I wish that the WP would allow me to use Greek characters like alpha, beta, gamma and delta as it would have made things a little more clear.

The fact that you agreed with my answer reminds me

"Great minds think alike, but fools seldom beg to differ"


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Health is a state of physical, mental and social wellbeing and not merely the absence of disease or infirmity :alien: I am not a jigsaw, I am a free man !

Diagnosed under the DSM5 rules with autism spectrum disorder, under DSM4 psychologist said would have been AS (299.80) but I suspect that I am somewhere between 299.80 and 299.00 (Autism) under DSM4.


bonez
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10 May 2009, 2:21 pm

lol so i guess i did that one correctly. Thanks alot for your help! I really appreciate it.

So I tried to use the same formula on this problem, but it didn't work? Or maybe I did a step wrong?

Given: b = 5 a = 15 and angle B = 50 degrees.
So I used Law of Sines: Sin A / a = Sin B / b
So Sin A / 15 = Sin 50 / 5 ,
So 5 * Sin A = 15 * Sin 50,
Sin A = (15 * Sin 50) / 5
which equals to 2.2.... which doesnt make sense because that's not a Sine value for a number.

Did I do a step wrong??

Thanks again



lau
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10 May 2009, 7:57 pm

bonez wrote:
lol so i guess i did that one correctly. Thanks alot for your help! I really appreciate it.

So I tried to use the same formula on this problem, but it didn't work? Or maybe I did a step wrong?

Given: b = 5 a = 15 and angle B = 50 degrees.
So I used Law of Sines: Sin A / a = Sin B / b
So Sin A / 15 = Sin 50 / 5 ,
So 5 * Sin A = 15 * Sin 50,
Sin A = (15 * Sin 50) / 5
which equals to 2.2.... which doesnt make sense because that's not a Sine value for a number.

Did I do a step wrong??

Thanks again

Nope. You are perfectly correct. There is no such triangle.

If you think it through, starting at the angle B, which is 50 degrees, you move 15 units out along side a. At this point, it is not possible to reach side b with a side c that is only 5 units long.


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