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Albirea
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19 Jun 2012, 9:09 pm

The same notation "system", as seen before (sharps and flats not included, and yes, there are both sharps [/i]andi/i] flats):

54334
654334 236
3453123 664
54334
654334 236
3453123 6234321
671432212111
671454322344
567765 4566544
212443 344


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jamieevren1210
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19 Jun 2012, 11:02 pm

I see everything-Sherlock Holmes, the game of shadows


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MakaylaTheAspie
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20 Jun 2012, 12:24 am

Wha...?


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Sparx
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20 Jun 2012, 3:01 am

Whut.



Albirea
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20 Jun 2012, 9:13 am

I've found the work function. Now how do I find the kinetic energy?

Why, physics, whyyyyyyyyyy????


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20 Jun 2012, 9:52 am

Going home tomorrow.


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Albirea
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20 Jun 2012, 9:55 am

All right, I've found the kinetic energy. It turns out to be the same as the work function. :huh:

WT[letter that implies word-not-found here]??????????


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kevinjh
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20 Jun 2012, 12:49 pm

Equal to but not equivalent, if memory serves me?



Albirea
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20 Jun 2012, 2:40 pm

So kinetic energy is the work function?
(We're talking about the photoelectric effect, by the way.)

(This is why I will fail physics in college.)


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kevinjh
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20 Jun 2012, 2:48 pm

Work function: energy of photon: dislodge electron: find: energy of electron: assume: conservation of energy



Albirea
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20 Jun 2012, 3:15 pm

I'M SORRY, I'M AFRAID I DON'T UNDERSTAND YOUR NOTATION. :oops:


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kevinjh
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20 Jun 2012, 3:21 pm

Energy before: energy of photon
Energy after: energy of electron
Energy is conserved



Albirea
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20 Jun 2012, 3:48 pm

I think I know what I did wrong now.

Given a wavelength of 2.50*10^-7 m, and a stopping potential of -2.66 V,

ΔV=hc/(eλ) - φ/e
-2.66 = ((6.63*10^-34)(3*10^8 ))/((1.06*10^-19)(2.5*10^-7)) - φ/(1.06*10^-19)
Find φ (work function): φ=1.07756*10^-18

Kinetic energy = hf-φ
=(6.63*10^-34)(1/(2.5*10^-7)) - 1.07756*10^-18
=1.07756*10^-18 J

That's the right answer... I think.


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Last edited by Albirea on 20 Jun 2012, 7:31 pm, edited 1 time in total.

MakaylaTheAspie
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20 Jun 2012, 7:04 pm

You all confuse me. :huh:


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Albirea
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20 Jun 2012, 7:19 pm

It's OK, that confuses me, too. :lol:

Here's one way to make the "lambda" symbol more interesting to the masses:

Image


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MakaylaTheAspie
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20 Jun 2012, 7:22 pm

:lol:

I already uploaded this, but what the heck?

Image


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