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Jamesy
Veteran
Joined: 24 Oct 2008
Age: 36
Gender: Male
Posts: 8,589
Location: Near London United Kingdom
19 Jan 2009, 11:37 am
19 Jan 2009, 12:01 pm
19 Jan 2009, 12:21 pm
42"
19 Jan 2009, 4:37 pm
19 Jan 2009, 5:10 pm
19 Jan 2009, 5:31 pm
20 Jan 2009, 12:21 pm
twoshots wrote:
Let's refine this discussion. Suppose we set our BMI to a target of 23 = lbs*703/ht^2.
Let a = the base fatassness, so 23 = 703a/ht =>
ht^2 = 30.6a => ht=5.5√a
Simply by plugging in someone with twice the fatassness, 2a, we derive a formula for ht' in terms of the lard of the smaller individual.
ht' = 5.5√2a
Thus
Δht = 5.5(√a)(√(2)-1) ~ 2.29√a
∴Δht ~ 2.29√a
Which is still non constant, of course...
Let a = the base fatassness, so 23 = 703a/ht =>
ht^2 = 30.6a => ht=5.5√a
Simply by plugging in someone with twice the fatassness, 2a, we derive a formula for ht' in terms of the lard of the smaller individual.
ht' = 5.5√2a
Thus
Δht = 5.5(√a)(√(2)-1) ~ 2.29√a
∴Δht ~ 2.29√a
Which is still non constant, of course...
Rain Man is among us!! !!
20 Jan 2009, 12:45 pm
twoshots wrote:
Let's refine this discussion. Suppose we set our BMI to a target of 23 = lbs*703/ht^2.
Let a = the base fatassness, so 23 = 703a/ht =>
ht^2 = 30.6a => ht=5.5√a
Simply by plugging in someone with twice the fatassness, 2a, we derive a formula for ht' in terms of the lard of the smaller individual.
ht' = 5.5√2a
Thus
Δht = 5.5(√a)(√(2)-1) ~ 2.29√a
∴Δht ~ 2.29√a
Which is still non constant, of course...
Let a = the base fatassness, so 23 = 703a/ht =>
ht^2 = 30.6a => ht=5.5√a
Simply by plugging in someone with twice the fatassness, 2a, we derive a formula for ht' in terms of the lard of the smaller individual.
ht' = 5.5√2a
Thus
Δht = 5.5(√a)(√(2)-1) ~ 2.29√a
∴Δht ~ 2.29√a
Which is still non constant, of course...
20 Jan 2009, 6:43 pm
What, you've never seen algebra before? I never even got into the fact that this is actually a 2 variable problem...
*weight of the smaller individual ranging from 100-300
*BMI ranging from 15 to 40
*height difference is the dependent variable
Overcomplication is always fun.
20 Jan 2009, 9:20 pm
Relicanth7
Veteran
Joined: 30 Sep 2007
Age: 33
Gender: Male
Posts: 1,896
Location: 'Murika... (Insert explicit word here) yeah!
20 Jan 2009, 9:45 pm
gemstone123 wrote:
twoshots wrote:
Let's refine this discussion. Suppose we set our BMI to a target of 23 = lbs*703/ht^2.
Let a = the base fatassness, so 23 = 703a/ht =>
ht^2 = 30.6a => ht=5.5√a
Simply by plugging in someone with twice the fatassness, 2a, we derive a formula for ht' in terms of the lard of the smaller individual.
ht' = 5.5√2a
Thus
Δht = 5.5(√a)(√(2)-1) ~ 2.29√a
∴Δht ~ 2.29√a
Which is still non constant, of course...
Let a = the base fatassness, so 23 = 703a/ht =>
ht^2 = 30.6a => ht=5.5√a
Simply by plugging in someone with twice the fatassness, 2a, we derive a formula for ht' in terms of the lard of the smaller individual.
ht' = 5.5√2a
Thus
Δht = 5.5(√a)(√(2)-1) ~ 2.29√a
∴Δht ~ 2.29√a
Which is still non constant, of course...
Now twoshots was the delta to refrence the change in height from person 1 to 2...
