My C++ Program Actually Works!

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Blake_be_cool
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19 Jan 2011, 4:14 am

I finally made something straight from scratch and it work how I wanted it to!

Quote:

/*
Name: Project1
Copyright:
Author: Blake James Reilly
Date: 19/01/11 17:26
Description:
*/

#include <iostream>

using namespace std;

int main (int argc, char *argv[])

{
string a, b, c, d;
a = "a";
string answer;

cout << "Select the first letter of the alphabet: " << endl;
cout << "a, b, c, d" << endl;
cin >> answer;

if (answer == a)
{
cout << "This is the right answer!" << endl;
}
else
{
cout << "Sorry this is the wrong answer." << endl;
}
system ("PAUSE");
}

/*Program Ended*/

Yes it is only very simple and basic.
But I'm proud that I did all of this from scratch...

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Helixstein
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19 Jan 2011, 4:15 am

Well done, Blake. :thumleft:

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betamaxx
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19 Jan 2011, 5:20 am

thats good:)
is this your first operational program, if so how many attempts did you make at it?

Blake_be_cool
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19 Jan 2011, 7:26 am

betamaxx wrote:

thats good:)
is this your first operational program, if so how many attempts did you make at it?

6th

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leejosepho
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19 Jan 2011, 8:12 am

Congratulations!

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Biokinetica
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19 Jan 2011, 12:04 pm

If you want, I can show you how to make that a switch statement that will look much cleaner and make things like this easier to edit later. If you're still interested after that, I'll show you how to make it a function call that will lower the amount memory the program needs (not that it's at all large).

kxmode
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19 Jan 2011, 12:15 pm

Blake_be_cool
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19 Jan 2011, 5:50 pm

Biokinetica wrote:

That would be awesome!

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nodice1996
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19 Jan 2011, 7:38 pm

I once tried to do something similar in perl script, but it never worked. I deleted the code when I switched from ubuntu to debian.

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Blake_be_cool
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19 Jan 2011, 8:13 pm

nodice1996 wrote:

I once tried to do something similar in perl script, but it never worked. I deleted the code when I switched from ubuntu to debian.

Do you know If I can still program C++ on Debian?
I've done A bit of search on it a while ago, and if I can still program on it I'll use it.

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nodice1996
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20 Jan 2011, 7:16 am

Blake_be_cool wrote:

nodice1996 wrote:

I once tried to do something similar in perl script, but it never worked. I deleted the code when I switched from ubuntu to debian.

Do you know If I can still program C++ on Debian?
I've done A bit of search on it a while ago, and if I can still program on it I'll use it.

It should work, but if you're moving from windows to *nix you'll need to recompile.

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LordoftheMonkeys
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20 Jan 2011, 8:50 am

Yes, it's a wonderful feeling when after a long, frustrating session of trying to get code to work, it finally comes out perfectly. I have had a lot of these progasms after coding in C.

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Biokinetica
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21 Jan 2011, 12:08 am

If you copy/paste this code into DevC++, it will compile as is.

Quote:

#include <iostream>
#include <string>
using namespace std;

int main(){
string a, b, c, d;
a = "a";
char answer; /*since you're only storing one character in "answer", you can just use the char data type.
This is also true for your other string variables, but it's not a problem here.
There's also an ascii hack for the cases, but that's really unnecessary */

cout << "Select the first letter of the alphabet: " << endl;
cout << "a, b, c, d" << endl;
cin >> answer;

switch (answer){

case 'a'://between the single quotes go your "options", or the possible values of var answer.

cout << "This is the right answer!" << endl;//after the colon, the code that you want to run if that case is true

break;//The "break" ends a loop. It has to come after a switch case unless there are multiple right answers to the question.

case 'b'://from here on, you can put in any

cout << "Sorry this is the wrong answer." << endl;

break;

case 'c':

cout << "Sorry this is the wrong answer." << endl;

break;

case 'd':

cout << "Sorry this is the wrong answer." << endl;

break;

//the default statement can be one line, or as many as you want provided you have the braces enclosing everything properly to define the scope
default:
{//A default statement MUST be present in order for the program to compile; can't get rid of it.
}

}
system ("PAUSE");
exit(0);//Same as "return 0;" in intmain()
}

Extra note: Strings are a special type of character data that can handle more than one character. The data type "char" is typically used (but not really mandatory) if you're only using one character to act as a variable.

Blake_be_cool
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21 Jan 2011, 2:09 am

Biokinetica wrote:

If you copy/paste this code into DevC++, it will compile as is.

Quote:

I don't understand most of this.

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Biokinetica
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21 Jan 2011, 2:29 am

I guess it's the commenting that's making it look scary. They're meant to explain the code, and in an IDE, they'll be color-coded like this.

Not to mention the formatting. I intentionally inserted extra spacing to make it readable.

Avarice
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27 Jan 2011, 1:41 am

Well done! It's always a nice feeling when a piece of code works. Unless it works on the very first try, then it doesn't feel quite right.

My first real program (i.e. One that does something that I need done more than once) was this. I still use it. If you have so time, you should try writing a problem to convert from C to F (or F to C.) It's a program you're going to need eventually, and it's nice to know that it's there and you made it.

Code:

/*Program designed to convert Fahrenheit temperatures to Celcius temperatures.*/

#include<stdio.h>
#include<stdlib.h>

int main()
{
    char fah1[50]; char i[50];
    int fah2; int celc; int i2;   
   
    printf("Would you like to convert a value from Fahrenheit to Celcius?(1=yes, 2=no)");
    gets(i);
    i2=atoi(i); 
    
    while(i2==1)
    {
            if(i2!=1) 
            {
                     return 0;
            }
            printf("Temperature in Celcius: ");
            gets(fah1);
            fah2=atoi(fah1);
    
            celc=(fah2*9/5) + 32;
    
            printf("Temperature in Fahrenheit: %d",celc);
            getchar();
            printf("Would you like to convert another value? (1=yes, 2=no)");
            gets(i);
            i2=atoi(i);
            
           while(i2==1)
            {
                    if(i2!=1)
                    {
                            return 0;
                    }
            printf("Temperature in Celcius: ");
            gets(fah1);
            fah2=atoi(fah1);
    
            celc=(fah2*9/5) + 32;
    
            printf("Temperature in Fahrenheit: %d",celc);
            getchar();
            printf("Would you like to convert another value? (1=yes, 2=no)");
            gets(i);
            i2=atoi(i);
              }         
    
    }
}

Yes. I know I probably shouldn't have used gets. Also, remember you can use [code] tags on this site, you don't need to use quotes.

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