en_una_isla wrote:
I'm embarrassed to admit this but this one has me stumped (it's from my son's math book). Can anyone figure it out?
2500 people took part in a cross country race. The number of adults is 4 times the number of children. If there were 1200 men, how many women were there?
Let a = the number of adults, m = the number of men, w = the number of women, c = the number of children, and t = the total number of people taking part in the race.
The total number of people taking part in the race, t, is 2500. So t = c + m + w.
The number of adults is 4 times c (4*c), so a = 4c.
1.) Replace the variables with the numbers you already know into the equation t = c + m + w and you get...
2500 = c + 1200 + w
If m + w (or 1200 + w), a, is equal to 4c, then you can also say the opposite, that c is equal to 1/4a (or 1/4(1200 + w)).
2.) Substitute 1/4a in the place of c to get...
2500 = 1/4(1200 + w) + 1200 + w
3.) Use the distributive property of multiplication to get...
2500 = 300 + w/4 + 1200 + w
4.) Subtract to get...
1000 = w/4 + w
5.) Multiply both sides by 4 to get...
4000 = w + 4w
6.) Add to get...
4000 = 5w
7.) Divide to get the number of women who took part in the cross country race.